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9p^2-6p-29=6
We move all terms to the left:
9p^2-6p-29-(6)=0
We add all the numbers together, and all the variables
9p^2-6p-35=0
a = 9; b = -6; c = -35;
Δ = b2-4ac
Δ = -62-4·9·(-35)
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1296}=36$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-36}{2*9}=\frac{-30}{18} =-1+2/3 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+36}{2*9}=\frac{42}{18} =2+1/3 $
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